find the value of this question guys
Attachments:
Answers
Answered by
1
Answer:
2^2x - 3.2^(x+2) + 32
= (2^x)^2 - 3.2^x.2^2 + 2^5
let 2^x be y,
=y^2 - 12y + 32
=y^2 - 8y - 4y + 32
=y(y - 8) - 4(y - 8)
=(y - 4)(y - 8)
now ,
(2^x - 4)(2^x - 8)=0
2^x=4 OR 2^x=8
2^x=2^2 OR 2^x=2^3
x=2 Or x=3
Step-by-step explanation:
Similar questions