Question

find the value of this question guys​

Answer 1

Answer:

2^2x - 3.2^(x+2) + 32

= (2^x)^2 - 3.2^x.2^2 + 2^5

let 2^x be y,

=y^2 - 12y + 32

=y^2 - 8y - 4y  + 32

=y(y - 8) - 4(y - 8)

=(y - 4)(y - 8)

now ,

(2^x - 4)(2^x - 8)=0

2^x=4 OR 2^x=8

2^x=2^2 OR 2^x=2^3

x=2 Or x=3

Step-by-step explanation: