Question

find the value of this question..please

Answer 1

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TanA + CotA = 4



On squaring both sides , we get



( TanA + CotA )² = (4)²



Tan²A + Cot²A + 2 × TanA × CotA = 16



Tan²A + Cot²A + 2 × TanA × 1/TanA = 16




Tan² A + Cot²A + 2 = 16


Tan² A + Cot²A = 16 - 2


Tan²A + Cot²A = 14



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Answer 2

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give :

tanA + cotA =4

to find

x^2+y^2=?


→on squaring both side we get:

»»tan^2+cot^2 A +2tanA.CotA=16

»»tan^2A+cot^2A=16-2(sinA/cosA).(cosA/sinA)

»»tan^2A+Cot^2A=16-2

»»tan^2A+Cot^2A=14

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