Question

find the value of trigonometric functions sec8π/3 class11​

Answer 1

Answer:

-2

Step-by-step explanation:

$\sec{\frac{8\pi}{3}} = \sec{(2 \pi + \frac{2\pi}{3}})\\\\=> sec(\frac{2\pi}{3})\\\\=> -2$

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Answer 2

$sec \: x \: = \frac{1}{cos \: x}$

$= sec \: ( \frac{x}{3} ) = \frac{1}{cos \frac{x}{3} }$

$using \: the \: \frac{\pi}{3}, \frac{\pi}{6}, \frac{\pi}{2} \: \: triangle \\ with \: the \: side \: of \: length \: 1, \sqrt{3} \: and \: 2$

$we \: can \: obtain \: the \: exact \: value \: of \: \: \\ cos( \frac{\pi}{3}) = \frac{1}{2}$

$= sec( \frac{\pi}{3}) = \frac{1}{ \frac{1}{2} } = 2$