Question

find the value of trigonometry function tan 1215​

Answer 1

Answer:

Tan(1215) = -1

Step-by-step explanation:

Tan(x+180 m) = tan(m)

Tan( 1215 ) = Tan( 180*6 + 135) = Tan(135)

Tan( 90+ x ) = -Cot(x)

Tan(135) = tan( 90 +45) = -Cot(45) = -1

Answer 2

To find:

The value of $\mathsf{tan1215^{\circ}}$

Before we solve the problem, we must clear some trigonometric concepts.

• $\mathsf{tan(180^{\circ}+\theta)=tan\theta}$
• $\mathsf{tan(180^{\circ}-\theta)=-tan\theta}$
• $\mathsf{tan(m\times 180^{\circ}+\theta)=tan\theta}$
• $\mathsf{tan(m\times 180^{\circ}-\theta)=-tan\theta}$

where $\mathsf{m\in {\mathbb{Z}}^{+}}$ and $\mathsf{\theta}$ is an acute angle.

Step-by-step explanation:

Now, $\mathsf{tan1215^{\circ}}$

$\mathsf{=tan(1260^{\circ}-45^{\circ})}$

$\mathsf{=tan(7\times 180^{\circ}-45^{\circ})}$

$\mathsf{=-tan45^{\circ}}$

• using $\mathsf{tan(m\times 180^{\circ}-\theta)=-tan\theta}$, where $\mathsf{m\in {\mathbb{Z}}^{+}}$ and $\mathsf{\theta}$ is an acute angle.

$\mathsf{=-1}$

• since $\mathsf{tan45^{\circ}=1}$

Answer: $\boxed{\mathsf{tan1215^{\circ}=-1}}$