Question

FIND THE VALUE OF TWO MOLAR SPECIFIC HEAT OF NITROGEN GAS R=8.314. ......Y=1.41

Answer 1

Answer:

We know,

=> Cp - Cv = R .............. ( 1 )

=> γ = Cp/Cv

=> Cp = γCv

=> Cp = 1.41 Cv ........... ( 2 )

Now, from equation ( 1 )

=> 1.41Cv - Cv = 8.314

=> 0.41Cv = 8.314

=> Cv = 8.314/0.41

=> Cv = 20.27

Now, from equation ( 2 )

=> Cp = 1.41 Cv

=> Cp = 1.41 × 20 27

=> Cp = 28.58

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