Question

FIND THE VALUE OF TWO MOLAR SPECIFIC HEAT OF NITROGEN GAS R=8.314. ......Y=1.41

Answer 1

Explanation:

We know,

=> Cp - Cv = R .............. ( 1 )

=> γ = Cp/Cv

=> Cp = γCv

=> Cp = 1.41 Cv ........... ( 2 )

Now, from equation ( 1 )

=> 1.41Cv - Cv = 8.314

=> 0.41Cv = 8.314

=> Cv = 8.314/0.41

=> Cv = 20.27

Now, from equation ( 2 )

=> Cp = 1.41 Cv

=> Cp = 1.41 × 20 27

=> Cp = 28.58

Answer 2

Specific heat for constant pressure=28.592 kj/kg.mol.k

Specific heat for constant volume=20.278 kj/kg.mol.k

Given :

R = 8.314 KJ/Kg.mol.k

Υ = 1.41

Find : Molar specific heat =?

          That is Cp and Cv

Formula used :

Cp - Cv = R

Cp/Cv = Y

Explanation :

• R is molar gas constant or called it as universal gas constant
• And it can never change irrespective of gases.  

Cp - Cv = 8.314

Cp/Cv = 1.41  

Cp = 1.41Cv

Cp - Cv = 8.314

1.41Cv - Cv = 8.314

0.41Cv = 8.314

Cv = 8.314/0.41  

Cv =20.278  kj/kg.mol.k

Cp-Cv = 8.314  

Cp = 8.314 + 20.278

Cp = 28.592 kj/kg.mol.k

Note that : Cp is always grater than Cv by the value of characteristic gas constant

Therefore,

Specific heat for constant pressure=28.592 kj/kg.mol.k

Specific heat for constant volume=20.278 kj/kg.mol.k

To learn more…

1. The relationship between universal gas constant (ru) and the characteristic gas constant (rc) is

brainly.in/question/1450830

2. Characteristic gas constant for air in m per kelvin

brainly.in/question/3059450