Find the value of u and v
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<ABD = <BDA =X
2X+62 =180
X= 59
X+U+82 =180⁰
U = 39⁰
<BDC =U
2U+V =180
V = 120⁰
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Answer:
let angle ADB = x
angle ADB = angle ABD = x
{side opposite to equal angles are angles}
in triangle ADB
62° + 2x = 180°. {angle sum property}
2x = 118°
x = 59°
82° + u + angle ADB = 180°. { straight line}
82° + u + 59° =180°
141° + u = 180°
u = 39°
u = angle CDB
{ sides opposite to equal angles are equal}
angle CDB = 39 °
Now,
in triangle DCB
39° + 39° + v = 180°. {angle sum property}
78° + v = 180°
v = 102°
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