Question

Find the value of u for which the system of equation is consistant ( matrices) (ece semester1)
x+y+z=1
x+2y+3z=u
x+9y+9z=u²

Answer 1

Answer:

Given,

x+2y+3z=1

2x+y+3z=2

5x+5y+9z=4

we have,

determinant,

∣A∣ = 1(9−15)−2(18−15)+3(10−5)

∣A∣ = −6−6+15

∣A∣ = 3

∣A∣ ≠ 0

∣A∣ = determinant of coefficient matrix ≠ 0

Therefore,

there exists a unique solution ( only one solution)

U value is 2

and

U² value is 2 * 2 = 4

Answer 2

Step-by-step explanation:

(a+b)^2 = a^2+ b^2+ 2ab

a = 5

b = 6