Question

Find the value of underoot 5+2 underoot6​

Answer 1

$\sqrt{5} + 2 \sqrt{6}$

They are unlike terms which can't be further solved. so they will remain as it is.

Answer 2

Question:-

Find the value of underoot 5+2 underoot6

Solutions:-

$√(5+2√6=√x+√y$

$5+2√6=x+y+2√xy$

$x+y=5✓$ ,$xy=6$

From here get the value of x-y which will be 1.

You can do that by gettimg $x2+y2=13$

$(x−y)2=1$ From there it follows that

$x−y=1$

now solve a simultaneous to get $x= 3, y = 2$

AnsWeR:-

$\sf\fbox{√3+√2}$