Question

Find the value of unknown angles:

Answer 1

Answer:

1. in triangle ABC. (LET US INDICATE ANGLE symbol(⊙)

⊙A+⊙B+⊙C=180

50+60+x=180

110+x=180

x=180-110

x=70

2. in second triangle

⊙y=80

so angle x=180-(50+80)

x=180-130

x=50

3. in 3rd triangle

⊙x=60

so angle y =180-(60+30)

y=180-90

y=90

4. in triangleABC

⊙A=32

⊙B=x

⊙C=y

⊙ACD=65

⊙BCD=180

so ⊙BCD=⊙ACD+⊙C

=65+y=180

y=180-65

115

⊙A+⊙B+⊙C=180

32+x+115=180

147+x=180

x=180-147

x=33