Find the value of unknowns.
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please rate the answer value of x=5
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In ∆ABC,
AB^2 + BC^2 = AC^2 (Hypotenuse theorem, angleB = 90°)
3^2 + 4^2 = AC^2
9 + 16 = AC^2
AC^2 = 25
AC = 5 = xcm
In ∆CAD,
AD^2= DC^2 - AC^2
AD^2 = 13^2 - 5^2
AD^2 = 169 - 25
AD = 12= ycm
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