find the value of (vii), (viii), (ix), (x)
Attachments:
Answers
Answered by
0
27 = 3^3
81 = 3^4
so eq will become
3^-2 × 3^5 × 3^-3.
1/ (1/3) ^-3 =( 1/3)^3 =3^-3
answer is 3^0 = 1.
2) 64 = 2^6 = 2 ^ 3×2
2^3 + (2^3 +1)
8+9 = 17
36 = 6^2
now new eq =
(6^7 - 6^9)/6^5
now if you calcuate this you can get the answer ...
81 = 3^4
so eq will become
3^-2 × 3^5 × 3^-3.
1/ (1/3) ^-3 =( 1/3)^3 =3^-3
answer is 3^0 = 1.
2) 64 = 2^6 = 2 ^ 3×2
2^3 + (2^3 +1)
8+9 = 17
36 = 6^2
now new eq =
(6^7 - 6^9)/6^5
now if you calcuate this you can get the answer ...
Similar questions