Question

find the value of which is given in the pic​

Answer 1

Answer:

x(x^2+x-132)/x(x-11)

x(x+12)(x-11)/x(x-11)

x+12

Answer 2

$\tt \frac{{x}^{3}+{x}^{2}-132x}{x(x-11)} \\ \\ \tt \longrightarrow \frac{x({x}^{2} + x - 132)}{x(x - 11)} \\ \\ \tt \longrightarrow \frac{\cancel{x}({x}^{2} + 12x - 11x - 132)}{\cancel{x}(x -11)} \\ \\ \tt \longrightarrow \frac{ x(x+12) -11(x+12)}{x-11} \\ \\ \tt \longrightarrow \frac{(x+12)(x-11)}{(x-11)} \\ \\ \tt \longrightarrow \frac{(x+12)\cancel{(x-11)}}{\cancel{(x-11)}} \\ \\ \tt \longrightarrow x+12 \\ \\ \boxed{\bold{\underline{\red{\tt \frac{{x}^{3}+{x}^{2}-132x}{x(x-11)} = x + 12 }}}}$