Question

Find the value of which the given system of equations has infinitely many solutions. kx+3y=k-3,12x+ky=k

Answer 1

Step-by-step explanation:

For infinitely many solution

a1 /a2 = b1/b2 = c1/c2c .....(i)

K/12 = 3/K = -(K-3) / -K ...... (ii)

By condition (i) and (ii)

K^2 =36⇒K=±6 ...(i)

By, condition (i) and (ii)

3K=K^2 −3K

K^2 −6K=0

K(K−6)=0

K=0 or K=6 ...(ii)

So, by equation (i) and (ii)

K=6