Question

find the value of
(whole root 56+root56+root56+root56+....)+ 2^2

Answer 1

Answer:

whole root 56+√56+√56+√56= y

√56+√56+√56+..... can also be written as y

whole root 56+y = y

squaring on both sides

56+y = y²

y²-y-56 = 0

by middle term splitting

y²-8y+7y-56 = 0

y(y-8)+7(y-8)= 0

(y+7)(y-8)= 0

one of them should become zero

y+7= 0

y = -7

y-8= 0

y = 8

therefore y= 7,-8

y +2² = ?

2² = 4

by putting values

y = -7

-7+4 = -3

y = 8

8+4 = 12

therefore answer is -3 or 12.