Question

find the value of why in distance between points a (2,-2) and b(1-y) is 5​

Answer 1

By square of distance formula

25=(2-1)^2 +(-2+y)^2

24= y^2+4-4y

y^2-4y-20=0

solve to get possible values of y.

Answer 2

using distance formula

(x2- X1)^2+(y2-y1)=5

y=5