find the value of (x+1)² please explain step by step
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Answer:
(a+b)^2=a^2+b^2+2ab
(x+1)^2=(x)^2+(1)^2+2×x×1
=x^2+1+2x
Answered by
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(x+1)²
= x² + 2x1 + 1²....... by using the formula⤵
[(a²+b²) = a² + 2ab + b²]
= x² + 2x + 1
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