Math, asked by niteshrathore884, 7 months ago

find the value of x

1.) 3(2^x+1)-2^x+2+5=0​

Answers

Answered by Harshada2708
2

Answer:

3(2x {}^{2} + 1) - 2 {x}^{2} + 2 + 5 = 0 \\ 6 {x}^{2} + 3 - 2 {x}^{2} + 2 + 5 = 0 \\ 4 {x}^{2} + 10 = 0 \\ 4 \ {x}^{2} =  - 10 \\  {x}^{2} = \frac{ - 10}{4} \\x = \sqrt{ \frac{ - 10}{4} }

Hope it helps dear

Answered by nikita6010
0

Answer:

HELLO

 x \:  = \sqrt{ \frac{10}{4} } is \: ur \: answer \\ plz \: follow \: me \\ hope \: it \: helps \: u \:

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