Question

Find the value of x [(1/3)^-5×(1/3)^7=(1/3)^2x-1]


(⩔)​

Answer 1

$Find \: the \: value \: of \: x. \: \\ ( \frac{1}{3})^{ - 5} \times( \frac{1}{3})^{ 7} = ( \frac{1}{3})^{2x - 1} \\ \\ solution. \\ \\ ( \frac{1}{3})^{ - 5} \times( \frac{1}{3})^{ 7} = ( \frac{1}{3})^{2x - 1} \\ \\ ( \frac{1}{3})^{( - 5 + 7)} = ( \frac{1}{3})^{2x - 1} \\ \\ - 5 + 7 = 2x - 1 \\ \\ 2 = 2x - 1 \\ \\ 2 + 1 = 2x \\ \\ 3 = 2x \\ \\ \frac{3}{2} = x \\ or\\ x = \frac{3}{2 } = 1.5 \: \: is \: the \: answer...$