Question

find the value of x

1.root3×tan2x=cos60°+sin45°×cos45°.

CORECT ANSWER AS ELL WITH PROCEDURE WILL BE AWARDED AS THE BRAINILIST ANSWER.
ALL THE BEST

Answer 1

Note: 

$cos 60 = \frac{1}{2} , sin 45 = \frac{1}{ \sqrt{2} } , cos 45 = \frac{1}{ \sqrt{2} }$

Explanation:

Given Equation is $\sqrt{3} tan2x = cos 60 + sin45 * cos 45$

$\sqrt{3} tan 2x = \frac{1}{2} * \frac{1}{ \sqrt{2} } * \frac{1}{ \sqrt{2} }$

$\sqrt{3} tan 2x = \frac{1}{2} + \frac{1}{2}$

$\sqrt{3} tan 2x = \frac{1 + 1}{2}$

$\sqrt{3} tan 2x = \frac{2}{2}$

$\sqrt{3} tan 2x = 1$

$tan 2x = \frac{1}{ \sqrt{3} }$

$tan 2x = tan 30$

2x = 30

x = 15.


Hope this helps!

Answer 2

hope it helps you
bro