find the value of (x+1/x)2
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Answered by
3
Answer:
Case 1:
[math]x>0[/math]
By applying the [math]AM-GM[/math] inequality, we get:
[math]x+1/x>=2[/math]
With equality holding for the case, [math]x=1/x = 1[/math]
So, [math]x- 1/x = 0[/math], for [math]x>0[/math]
Case 2:
[math]x<0[/math]
If [math]x<0[/math], then so is [math]1/x[/math].
But, if both are less than [math]0[/math], then their sum must also be less than[math] 0[/math], and hence cannot be [math]2[/math].
So, this case is void.
Hence, we get:
[math]x- 1/x = 0[/math], for all real x satisfying
Answered by
0
Answer:
x+1 =1x /x=1, 1 ×2 =2
Step-by-step explanation:
it is your answer
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