Math, asked by AnshulAgrawalAgrawal, 1 month ago

find the value of (X+1/x)^2​

Answers

Answered by Anonymous
4

Step-by-step explanation:

x+(1/x)=2

(x+(1/x))^2= 2^2

x^2 + 1/x^2 + 2= 4

x^2 + 1/x^2 = 2

(x-(1/x))^2 = x^2 + 1/x^2 - 2

=2–2 = 0

So, x-(1/x) = 0

Answered by akashsahi65
4

Step-by-step explanation:

x+(1/x)=2

(x+(1/x))^2= 2^2

x^2 + 1/x^2 + 2= 4

x^2 + 1/x^2 = 2

(x-(1/x))^2 = x^2 + 1/x^2 - 2

=2–2 = 0

So, x-(1/x) = 0

is this correct✅....

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