Question

Find the value of [x-1/x][x+1/x][x2+1/x2][x4+1/x4]​

Answer 1

Answer:

We know that,

(a+b)(a-b)=(a²-b²)

so,. {x-1/x}{x+1/x}=[x²-1/x²]

and {x²-1/x²}{x²+1/x²}=[x⁴-1/x⁴]

and {x⁴-1/x⁴}{x⁴+1/x⁴}=[x8-1/x8]

hence, [x-1/x][x+1/x][x²+1/x²][x⁴+1/x⁴]=[x8-1/x8]