find the value of x
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x-[3x-(2x-5/10)]=(2x-57/6)-5/3
x-3x+(2x+5/10)=(2x-57/6)-5/3
-2x+(2x+5/10)=(2x-57/6)-5/3
2x+5/10=(2x-57/6)-5/3+2x
2x+5=(2x-57/6)-5/3+2x×10
5+5/3=(2x-57/6)×10+2x-2x
5+5/3=(2x-57/6)×10
(15+5/3)=(2x-57/3)×5
20/3=(2x-57/3)×5
20/3×3/5=2x-57
4+57=2x
61=2x
61/2 =x
therefore, the value of x is 61/2
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