Question

find the value of x. (119)³×(119)⁶=(119)^2x-1​

Answer 1

$= > (119) ^{3} \times (119)^{6} = (119) ^{2x -1 } \\ = > (119) ^{3 + 6} = (119) ^{2x -1 } \\ = > 3 + 6 = 2x - 1 \\ = > 9 = 2x - 1 \\ = > 2x = 10 \\ = > x = \frac{10}{2} \\ = > x = 5$

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