Find the value of x
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Answered by
0
((-3/4)^-9)^X = (-3/4)^-9
=> (-3/4)^-9x = (-3/4)^-9
=> X =1
=> (-3/4)^-9x = (-3/4)^-9
=> X =1
Anonymous:
a^x * a^y = a ^ (x+y)
Answered by
3
{ (3/4)^-6 ÷(3/4)^3 }^x = (3/4)^-9
we know,
x^m÷x^n = x^(m -n)
use this ,
{ (3/4)^(-6-3)}^x = (3/4)^-9
{(3/4)^-9}^x = (3/4)^-9
we know,
(x^m)^n = x^mn
use this here,
(3/4)^-9x = (3/4)^-9
we know,
x^m = x^n
then, m = n
use this here,
-9x = -9
x = -9/-9 = 1
hence, x = 1
we know,
x^m÷x^n = x^(m -n)
use this ,
{ (3/4)^(-6-3)}^x = (3/4)^-9
{(3/4)^-9}^x = (3/4)^-9
we know,
(x^m)^n = x^mn
use this here,
(3/4)^-9x = (3/4)^-9
we know,
x^m = x^n
then, m = n
use this here,
-9x = -9
x = -9/-9 = 1
hence, x = 1
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