Question

find the value of x​

Answer 1

Step-by-step explanation:

$( { \frac{5}{7} )}^{2} \times { \frac{7}{5} }^{3x + 1} = { \frac{5}{7} }^{4} \\ {1}^{2 + 3x + 1} = \frac{ {5}^{4} }{ {7}^{4} } \\ {5}^{4} = {7}^{3x + 7} \\ \\ 3x + 7 = 4 \\ x = - 1$