Question

find the value of x. ​

Answer 1

Answer:

In the first figure x=52°(alternate angles are equal)

In the second figure x=148°

because angle Q=47,P=65+20,S=?

47+65+20+x=180(linear pair)

132+x=180

x=180-132

x=48°

Answer 2

Answer:

Solution of question 1=》

z= 52 ( v.o.A)

y= 180-112=68

A= sum of tringle is 180

52+68+x=180

x+120=180

x=180-120

x=60

Hence , x=60 , y= 68, z=52

Solution of question 2=》

Qps is a st. line 65+20+x=180

= x+85=180

= x=180-85

x=95

In triangle pQT

65+47+y= 180

y+112=180

y=180-112

y=68

QtP is a st. line

68+∠pTR = 180

∠pTR=112

In tringle PTR

20+ 112+z=180

132+z= 180

z=180-132

z=48

Hence , x= 95, y= 68, z=48

Hope you like my answer.....☆☆