find the value of x
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In ∆ ABC,
angle ACB =180°-(90+50)°(since sum of all angles in a triangle is 180 °)
=180°-140°
=40°
In ∆ CDE,
angle EDC =x
=180°-(100+40)°(since sum of all angles in a triangle is 180°)
=180°-140°
=40°(ANS)
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