Math, asked by tasvibaliku, 4 months ago

find the value of x?
16 8 x
3 =(3 )(3 )

Answers

Answered by AdityaSharma200414
3

Answer

Multiply by 112 both sides

7(3x+1)+16(2x-3)=14(x+3 )+8(3x-1)

Or 21x+7+32x-48=14x+42+24x-8

Or 21x+32x-14x-24x=42-8-7+48

Or 15x=75

Or x=5

Step-by-step explanation:

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Answered by gumnaambadshah
2

Answer:

Given that:

(a + b + c)² = 32

ab + bc + ca = 10

To find:

a² + b² + c²

Solution:

ATQ:

\sf \Longrightarrow (a + b + c)^2 = 32⟹(a+b+c)

2

=32

| We know that:

| (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ac

\sf \Longrightarrow a^2 + b^2 + c^2 + 2ab + 2bc + 2ac = 32⟹a

2

+b

2

+c

2

+2ab+2bc+2ac=32

Taking 2 as a common term from 2ab, 2bc & 2ac we get:

\sf \Longrightarrow a^2 + b^2 + c^2 + 2(ab + bc + ac) = 32⟹a

2

+b

2

+c

2

+2(ab+bc+ac)=32

| ATQ:

| ab + bc + ca = 10

| Substitute this value above.

\sf \Longrightarrow a^2 + b^2 + c^2 + 2(10) = 32⟹a

2

+b

2

+c

2

+2(10)=32

\sf \Longrightarrow a^2 + b^2 + c^2 + 20 = 32⟹a

2

+b

2

+c

2

+20=32

\sf \Longrightarrow a^2 + b^2 + c^2 = 32 - 20⟹a

2

+b

2

+c

2

=32−20

\sf \Longrightarrow a^2 + b^2 + c^2 = 12⟹a

2

+b

2

+c

2

=12

Final answer: 12

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