Question

Find the value of x

Answer 1

Answer:

$( \frac{2}{3} ) {}^{ - 5} \times ( \frac{2}{3} ) {}^{12} = ( \frac{2}{3} ) {}^{3x - 2}$

$( \frac{2}{3} ) {}^{ - 5 + 12} = ( \frac{2}{3} ) {}^{3x - 2}$

$( \frac{2}{3} ) {}^{7} = ( \frac{2}{3}) {}^{3x - 2}$

Comparing power of same base.

$7 = 3x - 2$

$7 + 2 = 3x$

$9 = 3x$

$x = \frac{9}{3}$

$x = 3$