Question

find the value of x??​

Answer 1

Step-by-step explanation:

Step-by-step explanation:

Given \: quadratic \: equation:\\2x^{2}+x-528=0

Splitting the middle term, we get

= 2x^{2}+33x-32x-528=0

= 2x^{2}+33x-16×2x-16×33=0

= x(2x+33)-16(2x+33)=0

=(2x+33)(x-16)=0

= (2x+33)=0\:Or\:x -16=0

= 2x=-33\:Or\:x=16

=x=- -33/2 or x=16

hope it helps