find the value of x??
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Step-by-step explanation:
Step-by-step explanation:
Given \: quadratic \: equation:\\2x^{2}+x-528=0
Splitting the middle term, we get
= 2x^{2}+33x-32x-528=0
= 2x^{2}+33x-16×2x-16×33=0
= x(2x+33)-16(2x+33)=0
=(2x+33)(x-16)=0
= (2x+33)=0\:Or\:x -16=0
= 2x=-33\:Or\:x=16
=x=- -33/2 or x=16
hope it helps
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