Math, asked by naitikthakkar, 2 months ago

find the value of x
(2^-1+4^-1+6^-1+8^-1)^x=1. ​

Answers

Answered by kanishkalahori14
0

Answer:

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Answered by MonoranjanDas
1

Step-by-step explanation:

sol {}^{n}

(2 {}^{ - 1}  + 4 {}^{ - 1}  + 6 {}^{ - 1}  + 8 {}^{ - 1}) {}^{x}  = 1

 =  > ( \frac{1}{2}  +  \frac{1}{4}  +  \frac{1}{6}  +  \frac{1}{8}) {}^{x}  = 1

 =  > ( \frac{12 + 6 + 4 + 3}{24} ) {}^{x}  = 1

 =  > ( \frac{25}{24} ) {}^{x}  = 1

 =  >  (\frac{25}{24} ) {}^{x}  = ( \frac{24}{25} ) {}^{0}

 =  > x = 0

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