Question

find the value of x
(2^-1+4^-1+6^-1+8^-1)^x=1. ​

Answer 1

Answer:

Three agents of modern education in IndiaThe British Government (East India Company)Christian missionariesIndian intellectuals and reformers

Answer 2

Step-by-step explanation:

$sol {}^{n}$

$(2 {}^{ - 1} + 4 {}^{ - 1} + 6 {}^{ - 1} + 8 {}^{ - 1}) {}^{x} = 1$

$= > ( \frac{1}{2} + \frac{1}{4} + \frac{1}{6} + \frac{1}{8}) {}^{x} = 1$

$= > ( \frac{12 + 6 + 4 + 3}{24} ) {}^{x} = 1$

$= > ( \frac{25}{24} ) {}^{x} = 1$

$= > (\frac{25}{24} ) {}^{x} = ( \frac{24}{25} ) {}^{0}$

$= > x = 0$