Question

find the value of x^2+1/x^2,if x-1/x=√3​

Answer 1

Answer:

$x^2+ \frac{1}{x^2 } = 11$

step by step:

$x -\binom{1}{x} = 3$

USING FORMULA:

$(a - b) ^{2}= {a}^{2} + {b}^{2} - 2ab$

$(x - \frac{1}{x} )^{2} = x + \frac{1}{ {x}^{2} } - 2(x \times \frac{1}{x}$

$( {3}^{2}) = {x}^{2} + \frac{1}{{x}^{2} } - 2$

$9 + 2 = {x}^{2} + \frac{1}{ {x}^{2} }$

${x}^{2} + \frac{1}{ {x}^{2} } = 11$