Question

find the value of x^2+1/x^2 if x-1/x=√3 fast its urgent!!!

Answer 1

Answer:

I think the answer is 5

please mark as brainliest

Step-by-step explanation:

Answer 2

AnswEr:-

Your Answer Is 5.

ExplanaTion:-

Given:-

$\tt\longrightarrow x - \dfrac{1}{x} = \sqrt{3} .$

To Find:-

The value of,

$\tt\longrightarrow {x}^{2} + \dfrac{1}{ {x}^{2} }.$

ID used:-

$\tt\longrightarrow(a - b) {}^{2} = {a}^{2} + {b}^{2} - 2ab.$

So Here,

It Is given that:-

$\tt\mapsto x - \dfrac{1}{x} = \sqrt{3} . \\ \\ \tt\mapsto(x - \frac{1}{x} ) {}^{2} = ( \sqrt{3} ) {}^{2} . \\ \\ \rm(squaring \: \: both \: \: sides). \\ \\ \tt\mapsto ({x})^{2} + ( \frac{1}{x } ) {}^{2} - 2 \times \cancel{x} \times \frac{1}{\cancel{x}} = ( \sqrt{3} \times \sqrt{3} ). \\ \\ \rm(by \: \: using \: \: the \: \: abov e \: \: id)\\ \\ \tt\mapsto {x}^{2} + \frac{1}{ {x}^{2} } - 2 = 3.\\ \\\tt\mapsto {x}^{2} + \frac{1}{x} = 3 + 2. \\ \\ \tt\mapsto\fbox{\underline{\underline{ {x}^{2} + \frac{1}{ {x}^{2} } = 5.}}}$

$\therefore$ Your Answer Is 5.