Find the value of x^2+1/x^2 when x = 4√15
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Given, x = 4√15
Now, x² + 1/x²
= (4√15)² + 1/(4√15)²
= (4 × 4 × √15 × √15) + 1/(4 × 4 × √15 × √15)
= (16 × 15) + 1/(16 × 15) [∵ √a × √a = √(a × a) = a]
= 240 - 1/240
= {(240 × 240) - 1}/240
= (240² - 1)/240
= (57600 - 1)/240
= 57599/240
#MarkAsBrainliest
Given, x = 4√15
Now, x² + 1/x²
= (4√15)² + 1/(4√15)²
= (4 × 4 × √15 × √15) + 1/(4 × 4 × √15 × √15)
= (16 × 15) + 1/(16 × 15) [∵ √a × √a = √(a × a) = a]
= 240 - 1/240
= {(240 × 240) - 1}/240
= (240² - 1)/240
= (57600 - 1)/240
= 57599/240
#MarkAsBrainliest
apurba6:
wrong
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