Math, asked by aysh994, 1 year ago

find the value of x (2*2*3*3)^2×=1296

Answers

Answered by TripathiVinayak2003
2

Answer:

Step-by-step explanation:

(2x2x3x3)^2x = 1296

(36)^2x = 1296

1296x =1296

Therefore, x = 1296/1296

X = 1

Answered by pratyush4211
1

(2 \times 2 \times 3 \times 3) {}^{2x}  = 1296

When you will prime factorise
1296=2×2×2×2×3×3×3×3
It can be written as

2²×2²×3²×3²
=(2×2×3×3)²

Now
( {2 \times 2 \times 3 \times 3})^{2x}  = ( {2 \times 2 \times 3 \times 3}^{2}

As you know when

When
Same number (a)
 {a}^{x}  =  {a}^{y}

Then
Same number will be remove and become

X=y

Just like Above
Both side are same
so,
2x=2
x=2/2
x=1

\boxed{\textsf{x=1}}
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