find the value of x (2*2*3*3)^2×=1296
Answers
Answered by
2
Answer:
Step-by-step explanation:
(2x2x3x3)^2x = 1296
(36)^2x = 1296
1296x =1296
Therefore, x = 1296/1296
X = 1
Answered by
1
When you will prime factorise
1296=2×2×2×2×3×3×3×3
It can be written as
2²×2²×3²×3²
=(2×2×3×3)²
Now
As you know when
When
Same number (a)
Then
Same number will be remove and become
X=y
Just like Above
Both side are same
so,
2x=2
x=2/2
x=1
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