Math, asked by theeducationGimmick, 1 year ago

Find the value of x^2 - 8y^3 - 36xy - 216 when X = 2y + 6

Answers

Answered by brijeshpbhkmp7yduj
0
the value of
x \times x - 8ycube - 36xy - 216when \\ x = 2y + 6 \\ x {  }^{2}   - 8y3 - 36xy - 216whenx  = 2y + 6 \\ x {}^{2}  - 512 y\:  \ \times :  2y- 36xy - 216when + 6 \\ x  {}^{2}  - 1024y - 36y - 216when + 6 \\ x {}^{2}  - 1060 - 216when + 6 \\ x {}^{2}  - 1276when + 6 \\ x {}^{2}  - 1276 + 6 \\ x {}^{2}  - 127
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