Question

find the value of x
[2/9]^3*[2/9]^-6=[2/9]^2x-1
Please answer this question I have exam tomorrow
if u give correct answer I'll mark u as brainliest ​

Answer 1

x=-1 is the correcr answer

Answer 2

SolutioN :-

$\longrightarrow \sf \bigg[ \frac{2}{9}\bigg ]^3 \times \bigg[ \frac{2}{9}\bigg ]^{-6}=\bigg[\frac{2}{9}\bigg]^{2x-1} \\ \\\longrightarrow \sf \bigg[ \frac{2}{9}\bigg ]^{3 + ( - 6)} = \bigg[ \frac{2}{9}\bigg ]^{2x - 1} \\ \\\longrightarrow \sf \bigg[ \frac{2}{9}\bigg ]^{ - 3} = \bigg[ \frac{2}{9}\bigg ]^{2x - 1} \\ \\\longrightarrow \sf - 3 = 2x - 1 \\ \\\longrightarrow \sf 2x = - 3 + 1 \\ \\\longrightarrow \sf 2x = - 2 \\ \\\longrightarrow \sf x = \frac{ - 2}{2} \\ \\ \longrightarrow \boxed{ \sf x = - 1}$