Math, asked by julius32, 4 months ago

find the value of x^2-k^2=0 at x= 0.3

Answers

Answered by sushil123456789
2

Answer:

Step-by-step explanation:

Formula:

Let any given quadratic equation be

ax² + bx + c = 0 ..... (1)

For equal roots, we have

discriminant = 0

i.e., b² - 4ac = 0

Step-by-step explanation:

The given equation is

x² + 2 (k + 1)x + k² = 0

Comparing with equation (1), we get

a = 1, b = 2 (k + 1), c = k²

For equal roots,

b² - 4ac = 0

or, {2 (k + 1)}² - 4 * 1 * k² = 0

or, 4 (k² + 2k + 1) - 4k² = 0

or, 4k² + 4 (2k + 1) - 4k² = 0

or, 4 (2k + 1) = 0

or, 2k + 1 = 0

or, 2k = - 1

or, k = - 1/2

Therefore, the value of k is (- 1/2).

Answered by Anonymous
3

Answer:

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