Question

Find the value of x, 2-logx=2log5-3log3+log36

Answer 1

$2 - log(x) = 2 log(5) - 3 log(3) + log(36) \\ \\ 2 - log(x) = log( {5}^{2} ) - 3 log( {3}^{3} ) + log(36)$

$2 - log(x) = log(25 ) - log( {9}) + log(36) \\ \\ 2 - log(x) = log( \frac{25 \times 36}{9} )$

$2 - log(x) = log( 100) \\ \\ 2 - log(x) = 2 \\ \\ log(x) = 0$

$x = {10}^{0} \\ \\ x = 1$