Math, asked by kumarayush9090, 5 months ago

find the value of x: (-2)power3 × (-2)power-6 = (-2)power2x-1​

Answers

Answered by rimadeb17
0

Answer:

sorry I tried my best but didn't get the answer .... I think there is some mistake in the question .... please recheck it ... and please if it is so then mark me as braniliest and follow me

Answered by Anonymous
5

\huge\underline\bold\pink{Answer}

 { (-2) }^{3}  \times  {( - 2)}^{ - 6}  =  {( - 2)}^{2x - 1}  \\  {( - 2)}^{3 + ( - 6)}  =  {( - 2)}^{2x - 1}  \\  {( - 2)}^{3 - 6}  =  {( - 2)}^{2x - 1}  \\  {( - 2)}^{ - 3}  =  {( - 2)}^{2x - 1}  \\ equating \: the \: powers \\  - 3 = 2x - 1 \\  - 3 + 1 = 2x \\  - 2 = 2x \\ x =  \frac{ - 2}{2}  \\ x =  - 1

Similar questions