Question

Find the value of x:2^x+1=4^2x-1​

Answer 1

Answer:

x = 1

Step-by-step explanation:

$2^{(x + 1)} = 4^{(2x - 1)}$ $= (2^2)^{(2x - 1)}$ $= 2^{(4x - 2)}$  [∵ $(a^m)^n = a^{mn}$]

∴ x + 1 = 4x - 2

∴ 4x - x = 1 + 2

∴ 3x = 3

∴ x = 1