Question

Find the value of x^2+y^2, if (x+y)^2 = 101 and the value of xy = 15​

Answer 1

Answer:

${(x + y)}^{2} = 101$

${x}^{2} + 2xy + {y}^{2} = 101$

${x}^{2} + 2(15) + {y}^{2} = 101$

x^2+30+y^2=101

x^2+y^2=101-30

x^2+y^2=71

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