Question

find the value of x​

Answer 1

Step-by-step explanation:

RQP is a right angle triangle

therefore you can find the value of x using Pythagoras theorem

therefore , (RP)2 = (RQ)2+ (PQ)2

,(17)2 = (15)2+(PQ)2

289= 225+(PQ)2

289-225 = (PQ)2

64=(PQ)2

√64= (PQ)2

PQ=8cm

therefore x=8 cm

Answer 2

Step-by-step explanation:

IN ∆PQR <PQR I. E <Q =90 DEGREES

So PR is Hypotenuse.

So (PR)^2= (PQ)^2 + (RQ)^2....... PYTHAGORAS THEOREM.

17^2= X^2 + 15^2

289= X^2 + 225

X^2 = 289-225

X^2 = 64

So by taking square root on both sides X = 8

I. e PQ = 8.