Question

Find the value of X​

Answer 1

Step-by-step explanation:

${(x + \frac{1}{x} + 2)}^{2} = 4 \\ = > x + \frac{1}{x} + 2 = \sqrt{4} \\ = > \frac{ {x}^{2} + 1 + 2x }{x} = 2 \\ = > {x}^{2} + 1 + 2x = 2x \\ = > {x}^{2} + 1 = 0 \\ = > x = \sqrt{ - 1}$

Answer 2

Answer:

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