find the value of x
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iv)
m ∠CBD+m ∠ABC=180°
=>120°+m ∠ABC=180°
=>m ∠ABC=180°-120°=60°
According to the question AB=AC
=>m ∠ABC=m ∠ACB=60°
in triangle ABC m ∠ABC+m ∠ACB+m ∠CAB=180°
=>m ∠CAB+60°+60°=180°
=>m ∠CAB=180°—120°=60°
v)like that try v number by yourself if you have any doubts regarding to this question please lemme know!
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