find the value of x
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Answer:
<CAD = 30° [<EAF=30°]
now, <BAD = 30°+x
so, 30°+x+10°+x+90°=180°
or, 130°+2x=180
or, 2x=180-150=30°
or, x=30/2=15°
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Answered by
0
Answer:
here in ΔADC
X+10 +X+30 +90 = 180 ( ∠ACD = 30° VERTICALLY OPPOSITE
2X = 50
X= 25°
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