Find the value of x, (2x-4)^2=0. Please fast
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Answered by
18
Answer:
Step-by-step explanation:
(2 X -4)² = 0
TAKING SQUARE ROOT ON BOTH SIDES
2 X -4 = 0
2 X = 4
X = 2.
HOPE THIS HELPS.
Answered by
0
Step-by-step explanation:
4x^2-16x+16=4(x^2-4x+4)
=4(x^2-2x-2x+4)
=4{x(x-2)-2(x-2) }=4{(x-2) (x-2) }
=4(x-2) ^2
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