Math, asked by ishanmmishra, 9 months ago

Find the value of x, (2x-4)^2=0. Please fast

Answers

Answered by raj3294
18

Answer:

Step-by-step explanation:

(2 X -4)² = 0

TAKING SQUARE ROOT ON BOTH SIDES

2 X -4 = 0

2 X = 4

X = 2.

HOPE THIS HELPS.

Answered by kaviya07
0

Step-by-step explanation:

4x^2-16x+16=4(x^2-4x+4)

=4(x^2-2x-2x+4)

=4{x(x-2)-2(x-2) }=4{(x-2) (x-2) }

=4(x-2) ^2

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