Find the
value of x
2x²+x-4=0
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1
Answer:
First we will use split the middle term method -
for that we will first divide the equation by 1/2,
The the equation will be,
= x² + x/2 - 4
By multiplying and dividing the middle term by 2 to get 2ab as we need get it as ,
(a² + b²) = a² + 2ab + b²
= x² + 2 × (1/4)x - 2 = 0
=> By adding (1/4)² both the sides ,
we get,
=> x² + 2(1/4)x + (1/4)² - 2 = (1/4)²
It can be, reduced to the form (a + b)²
=> ( x + 1/4 )² - 2 = 1/16
=> (x + 1/4)² = 1/16 + 2
=> (x + 1/16)² = (1 + 32)/16
=> (x+ 1/16)² = 33 / 16
By moving the square from LHS to RHS, we get,
=> x+ 1/4 = 33/16 route 2
=> x + 1/4 = (33 route 2) / 4 (or) x + 1/4 = (33 route 2) / 4
=> x = [ ( 33 route 2 )] - 1 / 4
HENCE ITS COMPLETE.
I HOPE ITS HELPFUL.
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